Discrete Fourier transform terms derivation The 2019 Stack Overflow Developer Survey Results Are In Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Discrete Fourier Transform interpreted in terms of sampling periodFourier Transform from Discrete Fourier TransformWhen does Discrete Fourier analysis fail to detect a frequency?Why are discrete-time Fourier series and discrete Fourier transform only defined on integer $k$?Approximating Fourier transform for range of output frequenciesFourier Transform Motivation/DerivationDifferentiability of discrete-time Fourier transformFourier Transform Notation in Signal ProcessingMeaning of sample points in nonuniform discrete Fourier transformFourier transform followed by discrete Fourier transform?
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Discrete Fourier transform terms derivation
The 2019 Stack Overflow Developer Survey Results Are In
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Discrete Fourier Transform interpreted in terms of sampling periodFourier Transform from Discrete Fourier TransformWhen does Discrete Fourier analysis fail to detect a frequency?Why are discrete-time Fourier series and discrete Fourier transform only defined on integer $k$?Approximating Fourier transform for range of output frequenciesFourier Transform Motivation/DerivationDifferentiability of discrete-time Fourier transformFourier Transform Notation in Signal ProcessingMeaning of sample points in nonuniform discrete Fourier transformFourier transform followed by discrete Fourier transform?
$begingroup$
According to the paper Lecture 7 - Discrete Fourier Transform we can approximate a Fourier transform
$$F(omega ) = int_ - infty ^infty f(t)e^ - jomega t$$
by the series
$$F(omega ) = sumlimits_k = 0^N - 1 f[k]e^ - jomega kT,$$
where $T$ is the sampling period, $kT$ is the $k$-th time moment. But why do they not multiply the terms of the series by the $dt = T$? And why are there no negative frequencies?
numerical-methods fourier-analysis fourier-series fourier-transform
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$endgroup$
add a comment |
$begingroup$
According to the paper Lecture 7 - Discrete Fourier Transform we can approximate a Fourier transform
$$F(omega ) = int_ - infty ^infty f(t)e^ - jomega t$$
by the series
$$F(omega ) = sumlimits_k = 0^N - 1 f[k]e^ - jomega kT,$$
where $T$ is the sampling period, $kT$ is the $k$-th time moment. But why do they not multiply the terms of the series by the $dt = T$? And why are there no negative frequencies?
numerical-methods fourier-analysis fourier-series fourier-transform
New contributor
James Flash is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
According to the paper Lecture 7 - Discrete Fourier Transform we can approximate a Fourier transform
$$F(omega ) = int_ - infty ^infty f(t)e^ - jomega t$$
by the series
$$F(omega ) = sumlimits_k = 0^N - 1 f[k]e^ - jomega kT,$$
where $T$ is the sampling period, $kT$ is the $k$-th time moment. But why do they not multiply the terms of the series by the $dt = T$? And why are there no negative frequencies?
numerical-methods fourier-analysis fourier-series fourier-transform
New contributor
James Flash is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
According to the paper Lecture 7 - Discrete Fourier Transform we can approximate a Fourier transform
$$F(omega ) = int_ - infty ^infty f(t)e^ - jomega t$$
by the series
$$F(omega ) = sumlimits_k = 0^N - 1 f[k]e^ - jomega kT,$$
where $T$ is the sampling period, $kT$ is the $k$-th time moment. But why do they not multiply the terms of the series by the $dt = T$? And why are there no negative frequencies?
numerical-methods fourier-analysis fourier-series fourier-transform
numerical-methods fourier-analysis fourier-series fourier-transform
New contributor
James Flash is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
James Flash is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited Apr 8 at 13:56
Masacroso
13.1k41748
13.1k41748
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James Flash is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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asked Apr 8 at 12:15
James FlashJames Flash
1
1
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