Symbol for any number within a set for proofs The 2019 Stack Overflow Developer Survey Results Are In Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Mathematical symbol for “and”Symbol/notation/strategy for figuring out an unknown inequality?Solve for ? - undetermined inequality symbolIs there a symbol for plus and minus as opposed to plus or minus?Is there a symbol for ‘equal if defined’What is the difference between $implies$ and $or$?Anyone familiar with a mathematical symbol for “that is” / “to clarify” / “whereby”?Is there a standard symbol for a multiset version of the natural numbersSymbol for assignment of a truth-value?Notation in quotient rings
I could not break this equation. Please help me
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Symbol for any number within a set for proofs
The 2019 Stack Overflow Developer Survey Results Are In
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Mathematical symbol for “and”Symbol/notation/strategy for figuring out an unknown inequality?Solve for ? - undetermined inequality symbolIs there a symbol for plus and minus as opposed to plus or minus?Is there a symbol for ‘equal if defined’What is the difference between $implies$ and $or$?Anyone familiar with a mathematical symbol for “that is” / “to clarify” / “whereby”?Is there a standard symbol for a multiset version of the natural numbersSymbol for assignment of a truth-value?Notation in quotient rings
$begingroup$
I think it's simpler if I write down where I wanted to use this symbol, rather than trying to explain it in an abstract way. I'll give a simple example and then explain the actual problem I was working on.
Simple example: Let $a in mathbbN$ and $b in mathbbZ$, then $a * b in mathbbZ$. The symbol I'm looking for (let's say it's $cdot$) would be used like this: $mathbbN * mathbbZ = mathbbZ$
The example I was working on was to prove that the Hessian matrix, $H$, of a likelihood function for a normal distribution is negative definite at the solutions to the likelihood equations. Calculating $z^THz$ where $z = (a, b)^T$ gives:
$$z^THz = frac-a^2n^2S_xx+frac-b^2n^32S_xx^2$$
I know that
$a, b in mathbbR$ and $(a, b) ne (0, 0)$- $n in mathbbN^+$
- $S_xx in mathbbR_ge 0$
Then it can be shown that from the two elements that are added together only one can be zero under these conditions and the other one must be negative, so the Hessian is negative definite. Is there a symbol that I could use to show something like $-mathbbR^2mathbbN^2 = mathbbR^-$, etc. deriving the result?
The question is not about how to calculate the definiteness but if there is a symbol that could be used here?
Thanks,
Norbert
notation
$endgroup$
add a comment |
$begingroup$
I think it's simpler if I write down where I wanted to use this symbol, rather than trying to explain it in an abstract way. I'll give a simple example and then explain the actual problem I was working on.
Simple example: Let $a in mathbbN$ and $b in mathbbZ$, then $a * b in mathbbZ$. The symbol I'm looking for (let's say it's $cdot$) would be used like this: $mathbbN * mathbbZ = mathbbZ$
The example I was working on was to prove that the Hessian matrix, $H$, of a likelihood function for a normal distribution is negative definite at the solutions to the likelihood equations. Calculating $z^THz$ where $z = (a, b)^T$ gives:
$$z^THz = frac-a^2n^2S_xx+frac-b^2n^32S_xx^2$$
I know that
$a, b in mathbbR$ and $(a, b) ne (0, 0)$- $n in mathbbN^+$
- $S_xx in mathbbR_ge 0$
Then it can be shown that from the two elements that are added together only one can be zero under these conditions and the other one must be negative, so the Hessian is negative definite. Is there a symbol that I could use to show something like $-mathbbR^2mathbbN^2 = mathbbR^-$, etc. deriving the result?
The question is not about how to calculate the definiteness but if there is a symbol that could be used here?
Thanks,
Norbert
notation
$endgroup$
add a comment |
$begingroup$
I think it's simpler if I write down where I wanted to use this symbol, rather than trying to explain it in an abstract way. I'll give a simple example and then explain the actual problem I was working on.
Simple example: Let $a in mathbbN$ and $b in mathbbZ$, then $a * b in mathbbZ$. The symbol I'm looking for (let's say it's $cdot$) would be used like this: $mathbbN * mathbbZ = mathbbZ$
The example I was working on was to prove that the Hessian matrix, $H$, of a likelihood function for a normal distribution is negative definite at the solutions to the likelihood equations. Calculating $z^THz$ where $z = (a, b)^T$ gives:
$$z^THz = frac-a^2n^2S_xx+frac-b^2n^32S_xx^2$$
I know that
$a, b in mathbbR$ and $(a, b) ne (0, 0)$- $n in mathbbN^+$
- $S_xx in mathbbR_ge 0$
Then it can be shown that from the two elements that are added together only one can be zero under these conditions and the other one must be negative, so the Hessian is negative definite. Is there a symbol that I could use to show something like $-mathbbR^2mathbbN^2 = mathbbR^-$, etc. deriving the result?
The question is not about how to calculate the definiteness but if there is a symbol that could be used here?
Thanks,
Norbert
notation
$endgroup$
I think it's simpler if I write down where I wanted to use this symbol, rather than trying to explain it in an abstract way. I'll give a simple example and then explain the actual problem I was working on.
Simple example: Let $a in mathbbN$ and $b in mathbbZ$, then $a * b in mathbbZ$. The symbol I'm looking for (let's say it's $cdot$) would be used like this: $mathbbN * mathbbZ = mathbbZ$
The example I was working on was to prove that the Hessian matrix, $H$, of a likelihood function for a normal distribution is negative definite at the solutions to the likelihood equations. Calculating $z^THz$ where $z = (a, b)^T$ gives:
$$z^THz = frac-a^2n^2S_xx+frac-b^2n^32S_xx^2$$
I know that
$a, b in mathbbR$ and $(a, b) ne (0, 0)$- $n in mathbbN^+$
- $S_xx in mathbbR_ge 0$
Then it can be shown that from the two elements that are added together only one can be zero under these conditions and the other one must be negative, so the Hessian is negative definite. Is there a symbol that I could use to show something like $-mathbbR^2mathbbN^2 = mathbbR^-$, etc. deriving the result?
The question is not about how to calculate the definiteness but if there is a symbol that could be used here?
Thanks,
Norbert
notation
notation
edited Apr 8 at 12:41
Asaf Karagila♦
308k33441775
308k33441775
asked Apr 8 at 12:19
norbertknorbertk
1183
1183
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
The closest one would be applying an operand to a set:
Let $M,N$ be two sets and $circ$ a mathematical operation on elements of $M$ and $N$ (e.g. addition, multiplication,...). Then
$$M circ N := m circ n mid m in M, n in N.$$
So for example, $-mathbbN = -n mid n in mathbbN$ or $mathbbN cdotmathbbZ = mathbbZ$ or maybe the most prominent example: $V + W = v + w mid v in V, w in W$ for two vector spaces $V,W$.
In some cases, these operands on sets are commonly used, in other cases they are rather rare and it would be better to define or at least mention them first. You should also ask yourself if you really need this notation, so if a definition of it is really justified.
$endgroup$
$begingroup$
Thanks Dirk. I don't really need this notation, I was just curious if one exists. I was thinking of just simply using the symbols for the sets, but it gets confusing when I raise a set to a power, e.g. $mathbbR^2$ is a set for vectors of dimension 2 and in my example, I would need to say something like squaring any number from $mathbbR$ gives a result in $mathbbR$, kind of like $f(x) = x^2, f: mathbbR to mathbbR$ without defining $f$
$endgroup$
– norbertk
Apr 8 at 12:47
$begingroup$
@norbertk the ambiguity of squaring is a pain. You could probably write $mathbb R*mathbb Rsubseteqmathbb R$ or similar, but definitely make sure you announce that you're using this sort of notation if it's not common in your context.
$endgroup$
– Mark S.
Apr 9 at 11:48
add a comment |
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1 Answer
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1 Answer
1
active
oldest
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active
oldest
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active
oldest
votes
$begingroup$
The closest one would be applying an operand to a set:
Let $M,N$ be two sets and $circ$ a mathematical operation on elements of $M$ and $N$ (e.g. addition, multiplication,...). Then
$$M circ N := m circ n mid m in M, n in N.$$
So for example, $-mathbbN = -n mid n in mathbbN$ or $mathbbN cdotmathbbZ = mathbbZ$ or maybe the most prominent example: $V + W = v + w mid v in V, w in W$ for two vector spaces $V,W$.
In some cases, these operands on sets are commonly used, in other cases they are rather rare and it would be better to define or at least mention them first. You should also ask yourself if you really need this notation, so if a definition of it is really justified.
$endgroup$
$begingroup$
Thanks Dirk. I don't really need this notation, I was just curious if one exists. I was thinking of just simply using the symbols for the sets, but it gets confusing when I raise a set to a power, e.g. $mathbbR^2$ is a set for vectors of dimension 2 and in my example, I would need to say something like squaring any number from $mathbbR$ gives a result in $mathbbR$, kind of like $f(x) = x^2, f: mathbbR to mathbbR$ without defining $f$
$endgroup$
– norbertk
Apr 8 at 12:47
$begingroup$
@norbertk the ambiguity of squaring is a pain. You could probably write $mathbb R*mathbb Rsubseteqmathbb R$ or similar, but definitely make sure you announce that you're using this sort of notation if it's not common in your context.
$endgroup$
– Mark S.
Apr 9 at 11:48
add a comment |
$begingroup$
The closest one would be applying an operand to a set:
Let $M,N$ be two sets and $circ$ a mathematical operation on elements of $M$ and $N$ (e.g. addition, multiplication,...). Then
$$M circ N := m circ n mid m in M, n in N.$$
So for example, $-mathbbN = -n mid n in mathbbN$ or $mathbbN cdotmathbbZ = mathbbZ$ or maybe the most prominent example: $V + W = v + w mid v in V, w in W$ for two vector spaces $V,W$.
In some cases, these operands on sets are commonly used, in other cases they are rather rare and it would be better to define or at least mention them first. You should also ask yourself if you really need this notation, so if a definition of it is really justified.
$endgroup$
$begingroup$
Thanks Dirk. I don't really need this notation, I was just curious if one exists. I was thinking of just simply using the symbols for the sets, but it gets confusing when I raise a set to a power, e.g. $mathbbR^2$ is a set for vectors of dimension 2 and in my example, I would need to say something like squaring any number from $mathbbR$ gives a result in $mathbbR$, kind of like $f(x) = x^2, f: mathbbR to mathbbR$ without defining $f$
$endgroup$
– norbertk
Apr 8 at 12:47
$begingroup$
@norbertk the ambiguity of squaring is a pain. You could probably write $mathbb R*mathbb Rsubseteqmathbb R$ or similar, but definitely make sure you announce that you're using this sort of notation if it's not common in your context.
$endgroup$
– Mark S.
Apr 9 at 11:48
add a comment |
$begingroup$
The closest one would be applying an operand to a set:
Let $M,N$ be two sets and $circ$ a mathematical operation on elements of $M$ and $N$ (e.g. addition, multiplication,...). Then
$$M circ N := m circ n mid m in M, n in N.$$
So for example, $-mathbbN = -n mid n in mathbbN$ or $mathbbN cdotmathbbZ = mathbbZ$ or maybe the most prominent example: $V + W = v + w mid v in V, w in W$ for two vector spaces $V,W$.
In some cases, these operands on sets are commonly used, in other cases they are rather rare and it would be better to define or at least mention them first. You should also ask yourself if you really need this notation, so if a definition of it is really justified.
$endgroup$
The closest one would be applying an operand to a set:
Let $M,N$ be two sets and $circ$ a mathematical operation on elements of $M$ and $N$ (e.g. addition, multiplication,...). Then
$$M circ N := m circ n mid m in M, n in N.$$
So for example, $-mathbbN = -n mid n in mathbbN$ or $mathbbN cdotmathbbZ = mathbbZ$ or maybe the most prominent example: $V + W = v + w mid v in V, w in W$ for two vector spaces $V,W$.
In some cases, these operands on sets are commonly used, in other cases they are rather rare and it would be better to define or at least mention them first. You should also ask yourself if you really need this notation, so if a definition of it is really justified.
answered Apr 8 at 12:33
DirkDirk
4,658219
4,658219
$begingroup$
Thanks Dirk. I don't really need this notation, I was just curious if one exists. I was thinking of just simply using the symbols for the sets, but it gets confusing when I raise a set to a power, e.g. $mathbbR^2$ is a set for vectors of dimension 2 and in my example, I would need to say something like squaring any number from $mathbbR$ gives a result in $mathbbR$, kind of like $f(x) = x^2, f: mathbbR to mathbbR$ without defining $f$
$endgroup$
– norbertk
Apr 8 at 12:47
$begingroup$
@norbertk the ambiguity of squaring is a pain. You could probably write $mathbb R*mathbb Rsubseteqmathbb R$ or similar, but definitely make sure you announce that you're using this sort of notation if it's not common in your context.
$endgroup$
– Mark S.
Apr 9 at 11:48
add a comment |
$begingroup$
Thanks Dirk. I don't really need this notation, I was just curious if one exists. I was thinking of just simply using the symbols for the sets, but it gets confusing when I raise a set to a power, e.g. $mathbbR^2$ is a set for vectors of dimension 2 and in my example, I would need to say something like squaring any number from $mathbbR$ gives a result in $mathbbR$, kind of like $f(x) = x^2, f: mathbbR to mathbbR$ without defining $f$
$endgroup$
– norbertk
Apr 8 at 12:47
$begingroup$
@norbertk the ambiguity of squaring is a pain. You could probably write $mathbb R*mathbb Rsubseteqmathbb R$ or similar, but definitely make sure you announce that you're using this sort of notation if it's not common in your context.
$endgroup$
– Mark S.
Apr 9 at 11:48
$begingroup$
Thanks Dirk. I don't really need this notation, I was just curious if one exists. I was thinking of just simply using the symbols for the sets, but it gets confusing when I raise a set to a power, e.g. $mathbbR^2$ is a set for vectors of dimension 2 and in my example, I would need to say something like squaring any number from $mathbbR$ gives a result in $mathbbR$, kind of like $f(x) = x^2, f: mathbbR to mathbbR$ without defining $f$
$endgroup$
– norbertk
Apr 8 at 12:47
$begingroup$
Thanks Dirk. I don't really need this notation, I was just curious if one exists. I was thinking of just simply using the symbols for the sets, but it gets confusing when I raise a set to a power, e.g. $mathbbR^2$ is a set for vectors of dimension 2 and in my example, I would need to say something like squaring any number from $mathbbR$ gives a result in $mathbbR$, kind of like $f(x) = x^2, f: mathbbR to mathbbR$ without defining $f$
$endgroup$
– norbertk
Apr 8 at 12:47
$begingroup$
@norbertk the ambiguity of squaring is a pain. You could probably write $mathbb R*mathbb Rsubseteqmathbb R$ or similar, but definitely make sure you announce that you're using this sort of notation if it's not common in your context.
$endgroup$
– Mark S.
Apr 9 at 11:48
$begingroup$
@norbertk the ambiguity of squaring is a pain. You could probably write $mathbb R*mathbb Rsubseteqmathbb R$ or similar, but definitely make sure you announce that you're using this sort of notation if it's not common in your context.
$endgroup$
– Mark S.
Apr 9 at 11:48
add a comment |
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