Recombination in array The 2019 Stack Overflow Developer Survey Results Are InFinding Subset-Sum with low cardinalityalgorithm to minimise pairwise product sqaurerootfinding minimum sum of absolute differences betweens values of two sets..Minimum AND operation on subset$O(n log k)$ for merging of $k$ lists with total of $n$ elementsMake whole array as zeroHow to check if a number say 'k' can be formed by adding any number of elements in set/array A?Sum over all contiguous partitions of an arrayFind the maximum score in a game on arrayConsider the following recursive algorithm, which takes as input a sequence $left( a _ 1 , a _ 2 , ldots , a _ n right)$ of n numbers
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Recombination in array
The 2019 Stack Overflow Developer Survey Results Are InFinding Subset-Sum with low cardinalityalgorithm to minimise pairwise product sqaurerootfinding minimum sum of absolute differences betweens values of two sets..Minimum AND operation on subset$O(n log k)$ for merging of $k$ lists with total of $n$ elementsMake whole array as zeroHow to check if a number say 'k' can be formed by adding any number of elements in set/array A?Sum over all contiguous partitions of an arrayFind the maximum score in a game on arrayConsider the following recursive algorithm, which takes as input a sequence $left( a _ 1 , a _ 2 , ldots , a _ n right)$ of n numbers
$begingroup$
We have an array of subatomic particles each having a size k. the only possible operation is to combine any two elements to form an element that is the difference of the original two sizes. Find the smallest possible size of the atomic particle that can be formed.
Sample 1:-
30
10
8
Answer 1:- 2
The difference of 10 and 8 is 2 which is the minimum possible.
Sample 2:-
13 11 9 7 2
Answer 2: 0
The difference of 13 and 11 is 2 and then the array would be 9 7 2 2.
The minimum difference now of the updated array is 2-2 = 0.
Sample 3:-
1 4 6 10
Answer 3: 1
The minimum element is 1 as it is already present in the array.
algorithms
New contributor
$endgroup$
add a comment |
$begingroup$
We have an array of subatomic particles each having a size k. the only possible operation is to combine any two elements to form an element that is the difference of the original two sizes. Find the smallest possible size of the atomic particle that can be formed.
Sample 1:-
30
10
8
Answer 1:- 2
The difference of 10 and 8 is 2 which is the minimum possible.
Sample 2:-
13 11 9 7 2
Answer 2: 0
The difference of 13 and 11 is 2 and then the array would be 9 7 2 2.
The minimum difference now of the updated array is 2-2 = 0.
Sample 3:-
1 4 6 10
Answer 3: 1
The minimum element is 1 as it is already present in the array.
algorithms
New contributor
$endgroup$
add a comment |
$begingroup$
We have an array of subatomic particles each having a size k. the only possible operation is to combine any two elements to form an element that is the difference of the original two sizes. Find the smallest possible size of the atomic particle that can be formed.
Sample 1:-
30
10
8
Answer 1:- 2
The difference of 10 and 8 is 2 which is the minimum possible.
Sample 2:-
13 11 9 7 2
Answer 2: 0
The difference of 13 and 11 is 2 and then the array would be 9 7 2 2.
The minimum difference now of the updated array is 2-2 = 0.
Sample 3:-
1 4 6 10
Answer 3: 1
The minimum element is 1 as it is already present in the array.
algorithms
New contributor
$endgroup$
We have an array of subatomic particles each having a size k. the only possible operation is to combine any two elements to form an element that is the difference of the original two sizes. Find the smallest possible size of the atomic particle that can be formed.
Sample 1:-
30
10
8
Answer 1:- 2
The difference of 10 and 8 is 2 which is the minimum possible.
Sample 2:-
13 11 9 7 2
Answer 2: 0
The difference of 13 and 11 is 2 and then the array would be 9 7 2 2.
The minimum difference now of the updated array is 2-2 = 0.
Sample 3:-
1 4 6 10
Answer 3: 1
The minimum element is 1 as it is already present in the array.
algorithms
algorithms
New contributor
New contributor
New contributor
asked Apr 7 at 18:00
anonymousanonymous
1
1
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New contributor
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