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Autocorrelation and lags definition



The 2019 Stack Overflow Developer Survey Results Are InDefinition of definitionDefinition of an “Experiment” in ProbabilityDefinition of Time SeriesIs distance between two graphs defined somehow?Definition of the autocorrelation in Time seriesDifference between a given percent and the totalDense and sparse graphsEdge correlation in a graph (Erdős-Rényi, Configuration model, ecc)Understanding the definition of continuity in real analysisQuestions about ARIMA modelling










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$begingroup$


I'm looking for a way to define lags in autocorrelation graphs / corellograms. I understand how to interpret such a graph but can't define a lag in a clear concise manner. Does a definition for this concept already exist? If not, what would be a good way to construct it?










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    1












    $begingroup$


    I'm looking for a way to define lags in autocorrelation graphs / corellograms. I understand how to interpret such a graph but can't define a lag in a clear concise manner. Does a definition for this concept already exist? If not, what would be a good way to construct it?










    share|cite|improve this question











    $endgroup$














      1












      1








      1





      $begingroup$


      I'm looking for a way to define lags in autocorrelation graphs / corellograms. I understand how to interpret such a graph but can't define a lag in a clear concise manner. Does a definition for this concept already exist? If not, what would be a good way to construct it?










      share|cite|improve this question











      $endgroup$




      I'm looking for a way to define lags in autocorrelation graphs / corellograms. I understand how to interpret such a graph but can't define a lag in a clear concise manner. Does a definition for this concept already exist? If not, what would be a good way to construct it?







      statistics stochastic-processes terminology definition correlation






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      edited Apr 6 at 20:27









      Alexander Gruber

      20.1k25103174




      20.1k25103174










      asked Apr 3 at 16:36









      Sammy.dSammy.d

      467




      467




















          1 Answer
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          1












          $begingroup$

          You have a time series variable, $X$, with realizations at discrete points in time indexed by $t$, so the time series data is $x_1,x_2,ldots,x_T$.



          An autocorrelation asks to what degree realizations with a certain time difference - a lag - co-move. For example, the autocorrelation with a lag of 1 would compute the correlation of the following pairs: $(x_1,x_2)$; $(x_2,x_3)$; $(x_3,x_4)$, and so on. Formally, the lag $l$ defines $Corr(x_t,x_t+l)$. Informally, the lag defines the time-distance for which you compare realizations of the time series.



          An autocorrelation graph usually plots these correlations for different values of $l$, starting from $1$ to, say, $10$ (depends on context).



          For example, $x_t$ could denote the price of Microsoft at the end of day $t$, and the autocorrelation with lag $l=1$ tells you how much the stock price co-moves from day to day. The lag $l=365$ tells you how much the stock price today co-moves with the stock price next year.






          share|cite|improve this answer









          $endgroup$












          • $begingroup$
            Thank you so much! You've put it so clearly.
            $endgroup$
            – Sammy.d
            Apr 6 at 8:46











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          active

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          1












          $begingroup$

          You have a time series variable, $X$, with realizations at discrete points in time indexed by $t$, so the time series data is $x_1,x_2,ldots,x_T$.



          An autocorrelation asks to what degree realizations with a certain time difference - a lag - co-move. For example, the autocorrelation with a lag of 1 would compute the correlation of the following pairs: $(x_1,x_2)$; $(x_2,x_3)$; $(x_3,x_4)$, and so on. Formally, the lag $l$ defines $Corr(x_t,x_t+l)$. Informally, the lag defines the time-distance for which you compare realizations of the time series.



          An autocorrelation graph usually plots these correlations for different values of $l$, starting from $1$ to, say, $10$ (depends on context).



          For example, $x_t$ could denote the price of Microsoft at the end of day $t$, and the autocorrelation with lag $l=1$ tells you how much the stock price co-moves from day to day. The lag $l=365$ tells you how much the stock price today co-moves with the stock price next year.






          share|cite|improve this answer









          $endgroup$












          • $begingroup$
            Thank you so much! You've put it so clearly.
            $endgroup$
            – Sammy.d
            Apr 6 at 8:46















          1












          $begingroup$

          You have a time series variable, $X$, with realizations at discrete points in time indexed by $t$, so the time series data is $x_1,x_2,ldots,x_T$.



          An autocorrelation asks to what degree realizations with a certain time difference - a lag - co-move. For example, the autocorrelation with a lag of 1 would compute the correlation of the following pairs: $(x_1,x_2)$; $(x_2,x_3)$; $(x_3,x_4)$, and so on. Formally, the lag $l$ defines $Corr(x_t,x_t+l)$. Informally, the lag defines the time-distance for which you compare realizations of the time series.



          An autocorrelation graph usually plots these correlations for different values of $l$, starting from $1$ to, say, $10$ (depends on context).



          For example, $x_t$ could denote the price of Microsoft at the end of day $t$, and the autocorrelation with lag $l=1$ tells you how much the stock price co-moves from day to day. The lag $l=365$ tells you how much the stock price today co-moves with the stock price next year.






          share|cite|improve this answer









          $endgroup$












          • $begingroup$
            Thank you so much! You've put it so clearly.
            $endgroup$
            – Sammy.d
            Apr 6 at 8:46













          1












          1








          1





          $begingroup$

          You have a time series variable, $X$, with realizations at discrete points in time indexed by $t$, so the time series data is $x_1,x_2,ldots,x_T$.



          An autocorrelation asks to what degree realizations with a certain time difference - a lag - co-move. For example, the autocorrelation with a lag of 1 would compute the correlation of the following pairs: $(x_1,x_2)$; $(x_2,x_3)$; $(x_3,x_4)$, and so on. Formally, the lag $l$ defines $Corr(x_t,x_t+l)$. Informally, the lag defines the time-distance for which you compare realizations of the time series.



          An autocorrelation graph usually plots these correlations for different values of $l$, starting from $1$ to, say, $10$ (depends on context).



          For example, $x_t$ could denote the price of Microsoft at the end of day $t$, and the autocorrelation with lag $l=1$ tells you how much the stock price co-moves from day to day. The lag $l=365$ tells you how much the stock price today co-moves with the stock price next year.






          share|cite|improve this answer









          $endgroup$



          You have a time series variable, $X$, with realizations at discrete points in time indexed by $t$, so the time series data is $x_1,x_2,ldots,x_T$.



          An autocorrelation asks to what degree realizations with a certain time difference - a lag - co-move. For example, the autocorrelation with a lag of 1 would compute the correlation of the following pairs: $(x_1,x_2)$; $(x_2,x_3)$; $(x_3,x_4)$, and so on. Formally, the lag $l$ defines $Corr(x_t,x_t+l)$. Informally, the lag defines the time-distance for which you compare realizations of the time series.



          An autocorrelation graph usually plots these correlations for different values of $l$, starting from $1$ to, say, $10$ (depends on context).



          For example, $x_t$ could denote the price of Microsoft at the end of day $t$, and the autocorrelation with lag $l=1$ tells you how much the stock price co-moves from day to day. The lag $l=365$ tells you how much the stock price today co-moves with the stock price next year.







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Apr 3 at 22:35









          NamelessNameless

          2,7531333




          2,7531333











          • $begingroup$
            Thank you so much! You've put it so clearly.
            $endgroup$
            – Sammy.d
            Apr 6 at 8:46
















          • $begingroup$
            Thank you so much! You've put it so clearly.
            $endgroup$
            – Sammy.d
            Apr 6 at 8:46















          $begingroup$
          Thank you so much! You've put it so clearly.
          $endgroup$
          – Sammy.d
          Apr 6 at 8:46




          $begingroup$
          Thank you so much! You've put it so clearly.
          $endgroup$
          – Sammy.d
          Apr 6 at 8:46

















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