Probability 33 people in a group of 100,000 have the same birthday? Assuming years have 365,000 days. Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)At least two people have the same birthdayHaving birthday at the same dayProbability of being same birthday of at least three peopleWhat is the probability that from 23 people 2 people have their birthday on the same day?Group of $r$ people at least three people have the same birthday?What is the probability that at least 3 people have the same birthday in the same yearWhat is probability that at least $2$ people have same birthday from group of $N$ people?Birthday probability of $k$ people and $n$ days a year such that at least $2$ people have the same bdayBirthday Problem: Finding the Probability Three People Have the Same BirthdayProbability of at least $3$ people sharing the same birthday in a group of $n$ people
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Probability 33 people in a group of 100,000 have the same birthday? Assuming years have 365,000 days.
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)At least two people have the same birthdayHaving birthday at the same dayProbability of being same birthday of at least three peopleWhat is the probability that from 23 people 2 people have their birthday on the same day?Group of $r$ people at least three people have the same birthday?What is the probability that at least 3 people have the same birthday in the same yearWhat is probability that at least $2$ people have same birthday from group of $N$ people?Birthday probability of $k$ people and $n$ days a year such that at least $2$ people have the same bdayBirthday Problem: Finding the Probability Three People Have the Same BirthdayProbability of at least $3$ people sharing the same birthday in a group of $n$ people
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Probability 33 people in a group of 100,000 have the same birthday? Assuming years have 365,000 days. Would this Poisson Formula work?
Updated!
Note to OP: Probability of exactly $33$ people have the same birthday? Or probability of at least $33$ people have the same birthday? Or probability that exactly $33$ people have the same birthday and possibly another group of $33$ has the same (but different) birthday? Or probability that a given preselected group of 33 people have the same birthday? Or.....
probability poisson-distribution birthday
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show 7 more comments
$begingroup$
Probability 33 people in a group of 100,000 have the same birthday? Assuming years have 365,000 days. Would this Poisson Formula work?
Updated!
Note to OP: Probability of exactly $33$ people have the same birthday? Or probability of at least $33$ people have the same birthday? Or probability that exactly $33$ people have the same birthday and possibly another group of $33$ has the same (but different) birthday? Or probability that a given preselected group of 33 people have the same birthday? Or.....
probability poisson-distribution birthday
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$begingroup$
Probability of some set has exactly $33$? Or has at least $33$? Or some particular set of $33$ has the same birthday?
$endgroup$
– David G. Stork
Apr 8 at 18:15
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How many days are assumed in a year, $365$?
$endgroup$
– NazimJ
Apr 8 at 18:18
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@NazimJ: Do you think your answer would differ significantly if you used $364$ versus $365$? Doesn't every problem of this sort assume $365$?
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– David G. Stork
Apr 8 at 18:20
$begingroup$
I don't know what every problem assumes, that's why I ask. It could be the case that pigeonhole principle implies there is always 33 people with the same bday (who knows). And it could be the case pigeonhole principle only gives you enought buckets assuming 364 instead of 365 (i dont know, havent started working the problem out yet). So for me it matters, yes
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– NazimJ
Apr 8 at 18:26
$begingroup$
Possible duplicate of part of math.stackexchange.com/questions/3173697/…
$endgroup$
– lonza leggiera
Apr 8 at 18:27
|
show 7 more comments
$begingroup$
Probability 33 people in a group of 100,000 have the same birthday? Assuming years have 365,000 days. Would this Poisson Formula work?
Updated!
Note to OP: Probability of exactly $33$ people have the same birthday? Or probability of at least $33$ people have the same birthday? Or probability that exactly $33$ people have the same birthday and possibly another group of $33$ has the same (but different) birthday? Or probability that a given preselected group of 33 people have the same birthday? Or.....
probability poisson-distribution birthday
$endgroup$
Probability 33 people in a group of 100,000 have the same birthday? Assuming years have 365,000 days. Would this Poisson Formula work?
Updated!
Note to OP: Probability of exactly $33$ people have the same birthday? Or probability of at least $33$ people have the same birthday? Or probability that exactly $33$ people have the same birthday and possibly another group of $33$ has the same (but different) birthday? Or probability that a given preselected group of 33 people have the same birthday? Or.....
probability poisson-distribution birthday
probability poisson-distribution birthday
edited Apr 8 at 20:39
David G. Stork
12.2k41836
12.2k41836
asked Apr 8 at 18:00
Ian HoyosIan Hoyos
115
115
$begingroup$
Probability of some set has exactly $33$? Or has at least $33$? Or some particular set of $33$ has the same birthday?
$endgroup$
– David G. Stork
Apr 8 at 18:15
$begingroup$
How many days are assumed in a year, $365$?
$endgroup$
– NazimJ
Apr 8 at 18:18
$begingroup$
@NazimJ: Do you think your answer would differ significantly if you used $364$ versus $365$? Doesn't every problem of this sort assume $365$?
$endgroup$
– David G. Stork
Apr 8 at 18:20
$begingroup$
I don't know what every problem assumes, that's why I ask. It could be the case that pigeonhole principle implies there is always 33 people with the same bday (who knows). And it could be the case pigeonhole principle only gives you enought buckets assuming 364 instead of 365 (i dont know, havent started working the problem out yet). So for me it matters, yes
$endgroup$
– NazimJ
Apr 8 at 18:26
$begingroup$
Possible duplicate of part of math.stackexchange.com/questions/3173697/…
$endgroup$
– lonza leggiera
Apr 8 at 18:27
|
show 7 more comments
$begingroup$
Probability of some set has exactly $33$? Or has at least $33$? Or some particular set of $33$ has the same birthday?
$endgroup$
– David G. Stork
Apr 8 at 18:15
$begingroup$
How many days are assumed in a year, $365$?
$endgroup$
– NazimJ
Apr 8 at 18:18
$begingroup$
@NazimJ: Do you think your answer would differ significantly if you used $364$ versus $365$? Doesn't every problem of this sort assume $365$?
$endgroup$
– David G. Stork
Apr 8 at 18:20
$begingroup$
I don't know what every problem assumes, that's why I ask. It could be the case that pigeonhole principle implies there is always 33 people with the same bday (who knows). And it could be the case pigeonhole principle only gives you enought buckets assuming 364 instead of 365 (i dont know, havent started working the problem out yet). So for me it matters, yes
$endgroup$
– NazimJ
Apr 8 at 18:26
$begingroup$
Possible duplicate of part of math.stackexchange.com/questions/3173697/…
$endgroup$
– lonza leggiera
Apr 8 at 18:27
$begingroup$
Probability of some set has exactly $33$? Or has at least $33$? Or some particular set of $33$ has the same birthday?
$endgroup$
– David G. Stork
Apr 8 at 18:15
$begingroup$
Probability of some set has exactly $33$? Or has at least $33$? Or some particular set of $33$ has the same birthday?
$endgroup$
– David G. Stork
Apr 8 at 18:15
$begingroup$
How many days are assumed in a year, $365$?
$endgroup$
– NazimJ
Apr 8 at 18:18
$begingroup$
How many days are assumed in a year, $365$?
$endgroup$
– NazimJ
Apr 8 at 18:18
$begingroup$
@NazimJ: Do you think your answer would differ significantly if you used $364$ versus $365$? Doesn't every problem of this sort assume $365$?
$endgroup$
– David G. Stork
Apr 8 at 18:20
$begingroup$
@NazimJ: Do you think your answer would differ significantly if you used $364$ versus $365$? Doesn't every problem of this sort assume $365$?
$endgroup$
– David G. Stork
Apr 8 at 18:20
$begingroup$
I don't know what every problem assumes, that's why I ask. It could be the case that pigeonhole principle implies there is always 33 people with the same bday (who knows). And it could be the case pigeonhole principle only gives you enought buckets assuming 364 instead of 365 (i dont know, havent started working the problem out yet). So for me it matters, yes
$endgroup$
– NazimJ
Apr 8 at 18:26
$begingroup$
I don't know what every problem assumes, that's why I ask. It could be the case that pigeonhole principle implies there is always 33 people with the same bday (who knows). And it could be the case pigeonhole principle only gives you enought buckets assuming 364 instead of 365 (i dont know, havent started working the problem out yet). So for me it matters, yes
$endgroup$
– NazimJ
Apr 8 at 18:26
$begingroup$
Possible duplicate of part of math.stackexchange.com/questions/3173697/…
$endgroup$
– lonza leggiera
Apr 8 at 18:27
$begingroup$
Possible duplicate of part of math.stackexchange.com/questions/3173697/…
$endgroup$
– lonza leggiera
Apr 8 at 18:27
|
show 7 more comments
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$begingroup$
Probability of some set has exactly $33$? Or has at least $33$? Or some particular set of $33$ has the same birthday?
$endgroup$
– David G. Stork
Apr 8 at 18:15
$begingroup$
How many days are assumed in a year, $365$?
$endgroup$
– NazimJ
Apr 8 at 18:18
$begingroup$
@NazimJ: Do you think your answer would differ significantly if you used $364$ versus $365$? Doesn't every problem of this sort assume $365$?
$endgroup$
– David G. Stork
Apr 8 at 18:20
$begingroup$
I don't know what every problem assumes, that's why I ask. It could be the case that pigeonhole principle implies there is always 33 people with the same bday (who knows). And it could be the case pigeonhole principle only gives you enought buckets assuming 364 instead of 365 (i dont know, havent started working the problem out yet). So for me it matters, yes
$endgroup$
– NazimJ
Apr 8 at 18:26
$begingroup$
Possible duplicate of part of math.stackexchange.com/questions/3173697/…
$endgroup$
– lonza leggiera
Apr 8 at 18:27