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Intuitive meaning behind Non-central chi squared distribution



The 2019 Stack Overflow Developer Survey Results Are Inmaximum of two non central chi squared random variableChi Squared Distribution with $mu = 0$, $sigma^2 neq 1$pdf for non-central gamma distributionAsymptotic behavior of non-central $chi^2$ CDF in terms of the degree-of-freedom parameter $k$Difference of two non-central chi squared random variablesExpectation of a Non-Central Chi-Squared distributionsum of two independent scaled noncentral $chi$-squared random variablesHow can we write a non-central chi-squared distribution as gamma distribution?Find the pdf for the Non-central F-distribution.Probability density function (PDF) of a scaled non-central chi squared distribution










0












$begingroup$


Given a random variable $X$ that follows a non-central chi squared distribution with one degree of freedom and non-centrality parameter $theta^2$:



$f_X(x)=frac12sqrt2pi xe^-frac12(x+theta^2)(e^thetasqrt x+e^-thetasqrt x) quad xgeq 0$



It can be shown by using Taylor expansions for $e^pm thetasqrt x$ and the identity $Gamma(frac2i+12)=frac(2i)!phantomaGamma(frac12)i! phantoma2^2i$ that the density can be rewritten as:



$f_X(x)=sum_i=0^infty P(R=i)f_2i+1(x)$



Where $Rsim Poisson(fractheta^22)$ and $f_2i+1(x)$ denotes the $chi^2_2i+1$ density.



I have been struggling to find the intuitive meaning behind this equality, anyone has any idea?










share|cite|improve this question









$endgroup$
















    0












    $begingroup$


    Given a random variable $X$ that follows a non-central chi squared distribution with one degree of freedom and non-centrality parameter $theta^2$:



    $f_X(x)=frac12sqrt2pi xe^-frac12(x+theta^2)(e^thetasqrt x+e^-thetasqrt x) quad xgeq 0$



    It can be shown by using Taylor expansions for $e^pm thetasqrt x$ and the identity $Gamma(frac2i+12)=frac(2i)!phantomaGamma(frac12)i! phantoma2^2i$ that the density can be rewritten as:



    $f_X(x)=sum_i=0^infty P(R=i)f_2i+1(x)$



    Where $Rsim Poisson(fractheta^22)$ and $f_2i+1(x)$ denotes the $chi^2_2i+1$ density.



    I have been struggling to find the intuitive meaning behind this equality, anyone has any idea?










    share|cite|improve this question









    $endgroup$














      0












      0








      0





      $begingroup$


      Given a random variable $X$ that follows a non-central chi squared distribution with one degree of freedom and non-centrality parameter $theta^2$:



      $f_X(x)=frac12sqrt2pi xe^-frac12(x+theta^2)(e^thetasqrt x+e^-thetasqrt x) quad xgeq 0$



      It can be shown by using Taylor expansions for $e^pm thetasqrt x$ and the identity $Gamma(frac2i+12)=frac(2i)!phantomaGamma(frac12)i! phantoma2^2i$ that the density can be rewritten as:



      $f_X(x)=sum_i=0^infty P(R=i)f_2i+1(x)$



      Where $Rsim Poisson(fractheta^22)$ and $f_2i+1(x)$ denotes the $chi^2_2i+1$ density.



      I have been struggling to find the intuitive meaning behind this equality, anyone has any idea?










      share|cite|improve this question









      $endgroup$




      Given a random variable $X$ that follows a non-central chi squared distribution with one degree of freedom and non-centrality parameter $theta^2$:



      $f_X(x)=frac12sqrt2pi xe^-frac12(x+theta^2)(e^thetasqrt x+e^-thetasqrt x) quad xgeq 0$



      It can be shown by using Taylor expansions for $e^pm thetasqrt x$ and the identity $Gamma(frac2i+12)=frac(2i)!phantomaGamma(frac12)i! phantoma2^2i$ that the density can be rewritten as:



      $f_X(x)=sum_i=0^infty P(R=i)f_2i+1(x)$



      Where $Rsim Poisson(fractheta^22)$ and $f_2i+1(x)$ denotes the $chi^2_2i+1$ density.



      I have been struggling to find the intuitive meaning behind this equality, anyone has any idea?







      probability probability-distributions






      share|cite|improve this question













      share|cite|improve this question











      share|cite|improve this question




      share|cite|improve this question










      asked Apr 8 at 0:51









      Daniel OrdoñezDaniel Ordoñez

      572317




      572317




















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