Lower bound on the integral of averaging operator. The 2019 Stack Overflow Developer Survey Results Are InIs there a lower bound for $int_B_rf$ when $f$ is a positive function?The Lebesgue-Borel measuref the difference between two open balls tends to $0$ as the radii tend to $infty$Compare measures of two sets“Kind of Duality result” for the volume of a $d$-ballEstablishing a few properties of the lower and upper Lebesgue integralIs the gradient somehow 'hidden' behind Lebesgue differentiation theorem?Commutation of limits and integralA guess related to Lebesgue differentiation theoremProving the sharper form of the Lebesgue Differentiation TheoremHow to prove that $textarea( S_r(x) cap B_R(0)) leq textarea(S_R(0))$?
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Lower bound on the integral of averaging operator.
The 2019 Stack Overflow Developer Survey Results Are InIs there a lower bound for $int_B_rf$ when $f$ is a positive function?The Lebesgue-Borel measuref the difference between two open balls tends to $0$ as the radii tend to $infty$Compare measures of two sets“Kind of Duality result” for the volume of a $d$-ballEstablishing a few properties of the lower and upper Lebesgue integralIs the gradient somehow 'hidden' behind Lebesgue differentiation theorem?Commutation of limits and integralA guess related to Lebesgue differentiation theoremProving the sharper form of the Lebesgue Differentiation TheoremHow to prove that $textarea( S_r(x) cap B_R(0)) leq textarea(S_R(0))$?
$begingroup$
In the following I denote by $B(x,r)$ the ball centered at $x$ of radius $r$, and by $|B(x,r)|$ the measure of this ball.
I am trying to solve the following exercise.
Question
Let $f geq 0, R geq 0$ and $B_R$ a ball of radius $R$ in $mathbb R^d$.
Show that for every $0 < r< R$ we have
$$
int_B_R f leq C int_B_R left( frac1B(x,r) int_B(x,r) f right) d x,
$$
where $C$ is a constant only depending on $d$.
Attempt
When $f$ is bounded, using the Lebesgue differentiation theorem
I can show that there exists $R'$ such that for all $r in (0, R')$
it holds
$$
int_B_R f leq
2 int_B_R left( frac1B(x,r) int_B(x,r) f right) d x.
$$
So it remains to prove the inequality when $r in (R', R)$ and also generalize it for unbounded functions $f$. I am not sure how to proceed
from this
real-analysis measure-theory lebesgue-integral
$endgroup$
add a comment |
$begingroup$
In the following I denote by $B(x,r)$ the ball centered at $x$ of radius $r$, and by $|B(x,r)|$ the measure of this ball.
I am trying to solve the following exercise.
Question
Let $f geq 0, R geq 0$ and $B_R$ a ball of radius $R$ in $mathbb R^d$.
Show that for every $0 < r< R$ we have
$$
int_B_R f leq C int_B_R left( frac1B(x,r) int_B(x,r) f right) d x,
$$
where $C$ is a constant only depending on $d$.
Attempt
When $f$ is bounded, using the Lebesgue differentiation theorem
I can show that there exists $R'$ such that for all $r in (0, R')$
it holds
$$
int_B_R f leq
2 int_B_R left( frac1B(x,r) int_B(x,r) f right) d x.
$$
So it remains to prove the inequality when $r in (R', R)$ and also generalize it for unbounded functions $f$. I am not sure how to proceed
from this
real-analysis measure-theory lebesgue-integral
$endgroup$
add a comment |
$begingroup$
In the following I denote by $B(x,r)$ the ball centered at $x$ of radius $r$, and by $|B(x,r)|$ the measure of this ball.
I am trying to solve the following exercise.
Question
Let $f geq 0, R geq 0$ and $B_R$ a ball of radius $R$ in $mathbb R^d$.
Show that for every $0 < r< R$ we have
$$
int_B_R f leq C int_B_R left( frac1B(x,r) int_B(x,r) f right) d x,
$$
where $C$ is a constant only depending on $d$.
Attempt
When $f$ is bounded, using the Lebesgue differentiation theorem
I can show that there exists $R'$ such that for all $r in (0, R')$
it holds
$$
int_B_R f leq
2 int_B_R left( frac1B(x,r) int_B(x,r) f right) d x.
$$
So it remains to prove the inequality when $r in (R', R)$ and also generalize it for unbounded functions $f$. I am not sure how to proceed
from this
real-analysis measure-theory lebesgue-integral
$endgroup$
In the following I denote by $B(x,r)$ the ball centered at $x$ of radius $r$, and by $|B(x,r)|$ the measure of this ball.
I am trying to solve the following exercise.
Question
Let $f geq 0, R geq 0$ and $B_R$ a ball of radius $R$ in $mathbb R^d$.
Show that for every $0 < r< R$ we have
$$
int_B_R f leq C int_B_R left( frac1B(x,r) int_B(x,r) f right) d x,
$$
where $C$ is a constant only depending on $d$.
Attempt
When $f$ is bounded, using the Lebesgue differentiation theorem
I can show that there exists $R'$ such that for all $r in (0, R')$
it holds
$$
int_B_R f leq
2 int_B_R left( frac1B(x,r) int_B(x,r) f right) d x.
$$
So it remains to prove the inequality when $r in (R', R)$ and also generalize it for unbounded functions $f$. I am not sure how to proceed
from this
real-analysis measure-theory lebesgue-integral
real-analysis measure-theory lebesgue-integral
edited Apr 8 at 8:51
Little Bird
asked Apr 8 at 1:51
Little BirdLittle Bird
716
716
add a comment |
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