need help in Solving: $sqrt1-frac1x-sqrtx-frac1x=x-frac1x$ [on hold] The 2019 Stack Overflow Developer Survey Results Are InDomain of $sqrt1+frac1x$I need help with inequalitySolving a Radical Equation $5(sqrt1-x + sqrt1+x) = 6x + 8sqrt1-x^2$ (squaring doesn't help)Minimum of $left(frac1x+frac1y+frac1zright)left(sqrt x+sqrt y+sqrt zright)^2$How to solve this equation for $x$?$left(sqrt2-sqrt3right)^x + left(sqrt2+sqrt3right)^x = 2$Need help in solving $10x-frac1x=3$Find $A $ in $sqrt28+sqrt7=sqrtA$How to compute $sqrt1+2015sqrt1 + 2018 cdot 2016$Solving: $x - sqrtx+3 - 17 = 0$How to go about solving $x=2^frac1x$

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need help in Solving: $sqrt1-frac1x-sqrtx-frac1x=x-frac1x$ [on hold]



The 2019 Stack Overflow Developer Survey Results Are InDomain of $sqrt1+frac1x$I need help with inequalitySolving a Radical Equation $5(sqrt1-x + sqrt1+x) = 6x + 8sqrt1-x^2$ (squaring doesn't help)Minimum of $left(frac1x+frac1y+frac1zright)left(sqrt x+sqrt y+sqrt zright)^2$How to solve this equation for $x$?$left(sqrt2-sqrt3right)^x + left(sqrt2+sqrt3right)^x = 2$Need help in solving $10x-frac1x=3$Find $A $ in $sqrt28+sqrt7=sqrtA$How to compute $sqrt1+2015sqrt1 + 2018 cdot 2016$Solving: $x - sqrtx+3 - 17 = 0$How to go about solving $x=2^frac1x$










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$sqrt1-frac1x-sqrtx-frac1x=x-frac1x$



maybe it's possible by findings its domain but I tried it and I couldn't solve it










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put on hold as off-topic by Xander Henderson, Juniven, Cesareo, Shailesh, Eevee Trainer 2 days ago


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Xander Henderson, Juniven, Cesareo, Shailesh, Eevee Trainer
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  • $begingroup$
    Have a look here
    $endgroup$
    – Dr. Mathva
    Apr 6 at 17:59







  • 3




    $begingroup$
    title and body ............
    $endgroup$
    – Maria Mazur
    Apr 6 at 18:05










  • $begingroup$
    sorry for the mistake, I edited the title.
    $endgroup$
    – Mhmdhsyn
    Apr 6 at 20:46















-1












$begingroup$


$sqrt1-frac1x-sqrtx-frac1x=x-frac1x$



maybe it's possible by findings its domain but I tried it and I couldn't solve it










share|cite|improve this question









New contributor




Mhmdhsyn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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$endgroup$



put on hold as off-topic by Xander Henderson, Juniven, Cesareo, Shailesh, Eevee Trainer 2 days ago


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Xander Henderson, Juniven, Cesareo, Shailesh, Eevee Trainer
If this question can be reworded to fit the rules in the help center, please edit the question.















  • $begingroup$
    Have a look here
    $endgroup$
    – Dr. Mathva
    Apr 6 at 17:59







  • 3




    $begingroup$
    title and body ............
    $endgroup$
    – Maria Mazur
    Apr 6 at 18:05










  • $begingroup$
    sorry for the mistake, I edited the title.
    $endgroup$
    – Mhmdhsyn
    Apr 6 at 20:46













-1












-1








-1


2



$begingroup$


$sqrt1-frac1x-sqrtx-frac1x=x-frac1x$



maybe it's possible by findings its domain but I tried it and I couldn't solve it










share|cite|improve this question









New contributor




Mhmdhsyn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




$sqrt1-frac1x-sqrtx-frac1x=x-frac1x$



maybe it's possible by findings its domain but I tried it and I couldn't solve it







algebra-precalculus radicals






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Mhmdhsyn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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share|cite|improve this question









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share|cite|improve this question




share|cite|improve this question








edited Apr 6 at 20:45







Mhmdhsyn













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asked Apr 6 at 17:47









MhmdhsynMhmdhsyn

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83




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New contributor





Mhmdhsyn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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Mhmdhsyn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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put on hold as off-topic by Xander Henderson, Juniven, Cesareo, Shailesh, Eevee Trainer 2 days ago


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Xander Henderson, Juniven, Cesareo, Shailesh, Eevee Trainer
If this question can be reworded to fit the rules in the help center, please edit the question.







put on hold as off-topic by Xander Henderson, Juniven, Cesareo, Shailesh, Eevee Trainer 2 days ago


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Xander Henderson, Juniven, Cesareo, Shailesh, Eevee Trainer
If this question can be reworded to fit the rules in the help center, please edit the question.











  • $begingroup$
    Have a look here
    $endgroup$
    – Dr. Mathva
    Apr 6 at 17:59







  • 3




    $begingroup$
    title and body ............
    $endgroup$
    – Maria Mazur
    Apr 6 at 18:05










  • $begingroup$
    sorry for the mistake, I edited the title.
    $endgroup$
    – Mhmdhsyn
    Apr 6 at 20:46
















  • $begingroup$
    Have a look here
    $endgroup$
    – Dr. Mathva
    Apr 6 at 17:59







  • 3




    $begingroup$
    title and body ............
    $endgroup$
    – Maria Mazur
    Apr 6 at 18:05










  • $begingroup$
    sorry for the mistake, I edited the title.
    $endgroup$
    – Mhmdhsyn
    Apr 6 at 20:46















$begingroup$
Have a look here
$endgroup$
– Dr. Mathva
Apr 6 at 17:59





$begingroup$
Have a look here
$endgroup$
– Dr. Mathva
Apr 6 at 17:59





3




3




$begingroup$
title and body ............
$endgroup$
– Maria Mazur
Apr 6 at 18:05




$begingroup$
title and body ............
$endgroup$
– Maria Mazur
Apr 6 at 18:05












$begingroup$
sorry for the mistake, I edited the title.
$endgroup$
– Mhmdhsyn
Apr 6 at 20:46




$begingroup$
sorry for the mistake, I edited the title.
$endgroup$
– Mhmdhsyn
Apr 6 at 20:46










1 Answer
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In any case you can factorize like this: $1-dfrac1x=dfracx-1x=dfracx^2-1xtimesdfrac1x+1=left(x-dfrac1xright)timesdfrac1x+1$






share|cite|improve this answer









$endgroup$



















    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    0












    $begingroup$

    In any case you can factorize like this: $1-dfrac1x=dfracx-1x=dfracx^2-1xtimesdfrac1x+1=left(x-dfrac1xright)timesdfrac1x+1$






    share|cite|improve this answer









    $endgroup$

















      0












      $begingroup$

      In any case you can factorize like this: $1-dfrac1x=dfracx-1x=dfracx^2-1xtimesdfrac1x+1=left(x-dfrac1xright)timesdfrac1x+1$






      share|cite|improve this answer









      $endgroup$















        0












        0








        0





        $begingroup$

        In any case you can factorize like this: $1-dfrac1x=dfracx-1x=dfracx^2-1xtimesdfrac1x+1=left(x-dfrac1xright)timesdfrac1x+1$






        share|cite|improve this answer









        $endgroup$



        In any case you can factorize like this: $1-dfrac1x=dfracx-1x=dfracx^2-1xtimesdfrac1x+1=left(x-dfrac1xright)timesdfrac1x+1$







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Apr 6 at 18:15









        MannMann

        2,3501727




        2,3501727













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