need help in Solving: $sqrt1-frac1x-sqrtx-frac1x=x-frac1x$ [on hold] The 2019 Stack Overflow Developer Survey Results Are InDomain of $sqrt1+frac1x$I need help with inequalitySolving a Radical Equation $5(sqrt1-x + sqrt1+x) = 6x + 8sqrt1-x^2$ (squaring doesn't help)Minimum of $left(frac1x+frac1y+frac1zright)left(sqrt x+sqrt y+sqrt zright)^2$How to solve this equation for $x$?$left(sqrt2-sqrt3right)^x + left(sqrt2+sqrt3right)^x = 2$Need help in solving $10x-frac1x=3$Find $A $ in $sqrt28+sqrt7=sqrtA$How to compute $sqrt1+2015sqrt1 + 2018 cdot 2016$Solving: $x - sqrtx+3 - 17 = 0$How to go about solving $x=2^frac1x$
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need help in Solving: $sqrt1-frac1x-sqrtx-frac1x=x-frac1x$ [on hold]
The 2019 Stack Overflow Developer Survey Results Are InDomain of $sqrt1+frac1x$I need help with inequalitySolving a Radical Equation $5(sqrt1-x + sqrt1+x) = 6x + 8sqrt1-x^2$ (squaring doesn't help)Minimum of $left(frac1x+frac1y+frac1zright)left(sqrt x+sqrt y+sqrt zright)^2$How to solve this equation for $x$?$left(sqrt2-sqrt3right)^x + left(sqrt2+sqrt3right)^x = 2$Need help in solving $10x-frac1x=3$Find $A $ in $sqrt28+sqrt7=sqrtA$How to compute $sqrt1+2015sqrt1 + 2018 cdot 2016$Solving: $x - sqrtx+3 - 17 = 0$How to go about solving $x=2^frac1x$
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$sqrt1-frac1x-sqrtx-frac1x=x-frac1x$
maybe it's possible by findings its domain but I tried it and I couldn't solve it
algebra-precalculus radicals
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put on hold as off-topic by Xander Henderson, Juniven, Cesareo, Shailesh, Eevee Trainer 2 days ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Xander Henderson, Juniven, Cesareo, Shailesh, Eevee Trainer
add a comment |
$begingroup$
$sqrt1-frac1x-sqrtx-frac1x=x-frac1x$
maybe it's possible by findings its domain but I tried it and I couldn't solve it
algebra-precalculus radicals
New contributor
Mhmdhsyn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
put on hold as off-topic by Xander Henderson, Juniven, Cesareo, Shailesh, Eevee Trainer 2 days ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Xander Henderson, Juniven, Cesareo, Shailesh, Eevee Trainer
$begingroup$
Have a look here
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– Dr. Mathva
Apr 6 at 17:59
3
$begingroup$
title and body ............
$endgroup$
– Maria Mazur
Apr 6 at 18:05
$begingroup$
sorry for the mistake, I edited the title.
$endgroup$
– Mhmdhsyn
Apr 6 at 20:46
add a comment |
$begingroup$
$sqrt1-frac1x-sqrtx-frac1x=x-frac1x$
maybe it's possible by findings its domain but I tried it and I couldn't solve it
algebra-precalculus radicals
New contributor
Mhmdhsyn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
$sqrt1-frac1x-sqrtx-frac1x=x-frac1x$
maybe it's possible by findings its domain but I tried it and I couldn't solve it
algebra-precalculus radicals
algebra-precalculus radicals
New contributor
Mhmdhsyn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Mhmdhsyn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited Apr 6 at 20:45
Mhmdhsyn
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asked Apr 6 at 17:47
MhmdhsynMhmdhsyn
83
83
New contributor
Mhmdhsyn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Mhmdhsyn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Mhmdhsyn is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
put on hold as off-topic by Xander Henderson, Juniven, Cesareo, Shailesh, Eevee Trainer 2 days ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Xander Henderson, Juniven, Cesareo, Shailesh, Eevee Trainer
put on hold as off-topic by Xander Henderson, Juniven, Cesareo, Shailesh, Eevee Trainer 2 days ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Xander Henderson, Juniven, Cesareo, Shailesh, Eevee Trainer
$begingroup$
Have a look here
$endgroup$
– Dr. Mathva
Apr 6 at 17:59
3
$begingroup$
title and body ............
$endgroup$
– Maria Mazur
Apr 6 at 18:05
$begingroup$
sorry for the mistake, I edited the title.
$endgroup$
– Mhmdhsyn
Apr 6 at 20:46
add a comment |
$begingroup$
Have a look here
$endgroup$
– Dr. Mathva
Apr 6 at 17:59
3
$begingroup$
title and body ............
$endgroup$
– Maria Mazur
Apr 6 at 18:05
$begingroup$
sorry for the mistake, I edited the title.
$endgroup$
– Mhmdhsyn
Apr 6 at 20:46
$begingroup$
Have a look here
$endgroup$
– Dr. Mathva
Apr 6 at 17:59
$begingroup$
Have a look here
$endgroup$
– Dr. Mathva
Apr 6 at 17:59
3
3
$begingroup$
title and body ............
$endgroup$
– Maria Mazur
Apr 6 at 18:05
$begingroup$
title and body ............
$endgroup$
– Maria Mazur
Apr 6 at 18:05
$begingroup$
sorry for the mistake, I edited the title.
$endgroup$
– Mhmdhsyn
Apr 6 at 20:46
$begingroup$
sorry for the mistake, I edited the title.
$endgroup$
– Mhmdhsyn
Apr 6 at 20:46
add a comment |
1 Answer
1
active
oldest
votes
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In any case you can factorize like this: $1-dfrac1x=dfracx-1x=dfracx^2-1xtimesdfrac1x+1=left(x-dfrac1xright)timesdfrac1x+1$
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add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
In any case you can factorize like this: $1-dfrac1x=dfracx-1x=dfracx^2-1xtimesdfrac1x+1=left(x-dfrac1xright)timesdfrac1x+1$
$endgroup$
add a comment |
$begingroup$
In any case you can factorize like this: $1-dfrac1x=dfracx-1x=dfracx^2-1xtimesdfrac1x+1=left(x-dfrac1xright)timesdfrac1x+1$
$endgroup$
add a comment |
$begingroup$
In any case you can factorize like this: $1-dfrac1x=dfracx-1x=dfracx^2-1xtimesdfrac1x+1=left(x-dfrac1xright)timesdfrac1x+1$
$endgroup$
In any case you can factorize like this: $1-dfrac1x=dfracx-1x=dfracx^2-1xtimesdfrac1x+1=left(x-dfrac1xright)timesdfrac1x+1$
answered Apr 6 at 18:15
MannMann
2,3501727
2,3501727
add a comment |
add a comment |
$begingroup$
Have a look here
$endgroup$
– Dr. Mathva
Apr 6 at 17:59
3
$begingroup$
title and body ............
$endgroup$
– Maria Mazur
Apr 6 at 18:05
$begingroup$
sorry for the mistake, I edited the title.
$endgroup$
– Mhmdhsyn
Apr 6 at 20:46