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How do I solve this to represent the complex number in Cartesian coordinate


Cartesian and Polar Coordinaterepresent real number as case of complex numberHow to solve complex numberHow to solve $|z^2-1|<|z|^2$ where $z$ is a complex number?Complex Number on Cartesian Coordinate System QuestionExpress a complex number in the Cartesian formConverting Complex numbers into Cartesian FormNumber of solution(s) of a complex equationRaising complex number to high power - Cartesian formHow to add real number and complex number in polar form













1












$begingroup$


How do I solve this to represent the complex number in Cartesian coordinate



$$z=frace^fracpi3ie^frac23pi icdot 2e^fracpi6i$$



So I got this question as a homework and I am not able to solve it correctly. Any leads on how to solve this would help.










share|cite|improve this question









New contributor




ardentcoder is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$











  • $begingroup$
    What do you want to solve ?
    $endgroup$
    – blub
    Apr 5 at 17:48










  • $begingroup$
    The image link is given
    $endgroup$
    – ardentcoder
    Apr 5 at 17:48










  • $begingroup$
    Don't use links in your question and rather make the effort to type it using MathJax.
    $endgroup$
    – blub
    Apr 5 at 17:52










  • $begingroup$
    Sorry about that. Will use it from next time. New to stack exchange mathematics.
    $endgroup$
    – ardentcoder
    Apr 5 at 17:53















1












$begingroup$


How do I solve this to represent the complex number in Cartesian coordinate



$$z=frace^fracpi3ie^frac23pi icdot 2e^fracpi6i$$



So I got this question as a homework and I am not able to solve it correctly. Any leads on how to solve this would help.










share|cite|improve this question









New contributor




ardentcoder is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$











  • $begingroup$
    What do you want to solve ?
    $endgroup$
    – blub
    Apr 5 at 17:48










  • $begingroup$
    The image link is given
    $endgroup$
    – ardentcoder
    Apr 5 at 17:48










  • $begingroup$
    Don't use links in your question and rather make the effort to type it using MathJax.
    $endgroup$
    – blub
    Apr 5 at 17:52










  • $begingroup$
    Sorry about that. Will use it from next time. New to stack exchange mathematics.
    $endgroup$
    – ardentcoder
    Apr 5 at 17:53













1












1








1





$begingroup$


How do I solve this to represent the complex number in Cartesian coordinate



$$z=frace^fracpi3ie^frac23pi icdot 2e^fracpi6i$$



So I got this question as a homework and I am not able to solve it correctly. Any leads on how to solve this would help.










share|cite|improve this question









New contributor




ardentcoder is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




How do I solve this to represent the complex number in Cartesian coordinate



$$z=frace^fracpi3ie^frac23pi icdot 2e^fracpi6i$$



So I got this question as a homework and I am not able to solve it correctly. Any leads on how to solve this would help.







complex-numbers exponential-function






share|cite|improve this question









New contributor




ardentcoder is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|cite|improve this question









New contributor




ardentcoder is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|cite|improve this question




share|cite|improve this question








edited Apr 5 at 17:54









blub

3,289929




3,289929






New contributor




ardentcoder is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked Apr 5 at 17:47









ardentcoderardentcoder

84




84




New contributor




ardentcoder is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





ardentcoder is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






ardentcoder is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











  • $begingroup$
    What do you want to solve ?
    $endgroup$
    – blub
    Apr 5 at 17:48










  • $begingroup$
    The image link is given
    $endgroup$
    – ardentcoder
    Apr 5 at 17:48










  • $begingroup$
    Don't use links in your question and rather make the effort to type it using MathJax.
    $endgroup$
    – blub
    Apr 5 at 17:52










  • $begingroup$
    Sorry about that. Will use it from next time. New to stack exchange mathematics.
    $endgroup$
    – ardentcoder
    Apr 5 at 17:53
















  • $begingroup$
    What do you want to solve ?
    $endgroup$
    – blub
    Apr 5 at 17:48










  • $begingroup$
    The image link is given
    $endgroup$
    – ardentcoder
    Apr 5 at 17:48










  • $begingroup$
    Don't use links in your question and rather make the effort to type it using MathJax.
    $endgroup$
    – blub
    Apr 5 at 17:52










  • $begingroup$
    Sorry about that. Will use it from next time. New to stack exchange mathematics.
    $endgroup$
    – ardentcoder
    Apr 5 at 17:53















$begingroup$
What do you want to solve ?
$endgroup$
– blub
Apr 5 at 17:48




$begingroup$
What do you want to solve ?
$endgroup$
– blub
Apr 5 at 17:48












$begingroup$
The image link is given
$endgroup$
– ardentcoder
Apr 5 at 17:48




$begingroup$
The image link is given
$endgroup$
– ardentcoder
Apr 5 at 17:48












$begingroup$
Don't use links in your question and rather make the effort to type it using MathJax.
$endgroup$
– blub
Apr 5 at 17:52




$begingroup$
Don't use links in your question and rather make the effort to type it using MathJax.
$endgroup$
– blub
Apr 5 at 17:52












$begingroup$
Sorry about that. Will use it from next time. New to stack exchange mathematics.
$endgroup$
– ardentcoder
Apr 5 at 17:53




$begingroup$
Sorry about that. Will use it from next time. New to stack exchange mathematics.
$endgroup$
– ardentcoder
Apr 5 at 17:53










1 Answer
1






active

oldest

votes


















1












$begingroup$

Hint: For any $xinmathbb R$, you have



$$e^ix=cos(x)+isin(x)$$



also known as Euler's formula.




So, e.g. considering $e^fracpi3i$, as $pi/3inmathbb R$, we have



$$e^fracpi3i=cos(pi/3)+isin(pi/3)=frac12+ifracsqrt32$$



You can proceed to use this conversion of polar to cartesian representations to convert the other expressions. Then, you may proceed to do arithmetic on those cartesian-represented numbers as usual.






share|cite|improve this answer











$endgroup$












  • $begingroup$
    Yes I saw this equation online. So i have to use this and solve the equation first and represent in cartesian coordinate?
    $endgroup$
    – ardentcoder
    Apr 5 at 18:00










  • $begingroup$
    @ardentcoder I'll edit my answer.
    $endgroup$
    – blub
    Apr 5 at 18:01










  • $begingroup$
    Thank you . Will proceed with this.
    $endgroup$
    – ardentcoder
    Apr 5 at 18:33











Your Answer





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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









1












$begingroup$

Hint: For any $xinmathbb R$, you have



$$e^ix=cos(x)+isin(x)$$



also known as Euler's formula.




So, e.g. considering $e^fracpi3i$, as $pi/3inmathbb R$, we have



$$e^fracpi3i=cos(pi/3)+isin(pi/3)=frac12+ifracsqrt32$$



You can proceed to use this conversion of polar to cartesian representations to convert the other expressions. Then, you may proceed to do arithmetic on those cartesian-represented numbers as usual.






share|cite|improve this answer











$endgroup$












  • $begingroup$
    Yes I saw this equation online. So i have to use this and solve the equation first and represent in cartesian coordinate?
    $endgroup$
    – ardentcoder
    Apr 5 at 18:00










  • $begingroup$
    @ardentcoder I'll edit my answer.
    $endgroup$
    – blub
    Apr 5 at 18:01










  • $begingroup$
    Thank you . Will proceed with this.
    $endgroup$
    – ardentcoder
    Apr 5 at 18:33















1












$begingroup$

Hint: For any $xinmathbb R$, you have



$$e^ix=cos(x)+isin(x)$$



also known as Euler's formula.




So, e.g. considering $e^fracpi3i$, as $pi/3inmathbb R$, we have



$$e^fracpi3i=cos(pi/3)+isin(pi/3)=frac12+ifracsqrt32$$



You can proceed to use this conversion of polar to cartesian representations to convert the other expressions. Then, you may proceed to do arithmetic on those cartesian-represented numbers as usual.






share|cite|improve this answer











$endgroup$












  • $begingroup$
    Yes I saw this equation online. So i have to use this and solve the equation first and represent in cartesian coordinate?
    $endgroup$
    – ardentcoder
    Apr 5 at 18:00










  • $begingroup$
    @ardentcoder I'll edit my answer.
    $endgroup$
    – blub
    Apr 5 at 18:01










  • $begingroup$
    Thank you . Will proceed with this.
    $endgroup$
    – ardentcoder
    Apr 5 at 18:33













1












1








1





$begingroup$

Hint: For any $xinmathbb R$, you have



$$e^ix=cos(x)+isin(x)$$



also known as Euler's formula.




So, e.g. considering $e^fracpi3i$, as $pi/3inmathbb R$, we have



$$e^fracpi3i=cos(pi/3)+isin(pi/3)=frac12+ifracsqrt32$$



You can proceed to use this conversion of polar to cartesian representations to convert the other expressions. Then, you may proceed to do arithmetic on those cartesian-represented numbers as usual.






share|cite|improve this answer











$endgroup$



Hint: For any $xinmathbb R$, you have



$$e^ix=cos(x)+isin(x)$$



also known as Euler's formula.




So, e.g. considering $e^fracpi3i$, as $pi/3inmathbb R$, we have



$$e^fracpi3i=cos(pi/3)+isin(pi/3)=frac12+ifracsqrt32$$



You can proceed to use this conversion of polar to cartesian representations to convert the other expressions. Then, you may proceed to do arithmetic on those cartesian-represented numbers as usual.







share|cite|improve this answer














share|cite|improve this answer



share|cite|improve this answer








edited Apr 5 at 18:04

























answered Apr 5 at 17:51









blubblub

3,289929




3,289929











  • $begingroup$
    Yes I saw this equation online. So i have to use this and solve the equation first and represent in cartesian coordinate?
    $endgroup$
    – ardentcoder
    Apr 5 at 18:00










  • $begingroup$
    @ardentcoder I'll edit my answer.
    $endgroup$
    – blub
    Apr 5 at 18:01










  • $begingroup$
    Thank you . Will proceed with this.
    $endgroup$
    – ardentcoder
    Apr 5 at 18:33
















  • $begingroup$
    Yes I saw this equation online. So i have to use this and solve the equation first and represent in cartesian coordinate?
    $endgroup$
    – ardentcoder
    Apr 5 at 18:00










  • $begingroup$
    @ardentcoder I'll edit my answer.
    $endgroup$
    – blub
    Apr 5 at 18:01










  • $begingroup$
    Thank you . Will proceed with this.
    $endgroup$
    – ardentcoder
    Apr 5 at 18:33















$begingroup$
Yes I saw this equation online. So i have to use this and solve the equation first and represent in cartesian coordinate?
$endgroup$
– ardentcoder
Apr 5 at 18:00




$begingroup$
Yes I saw this equation online. So i have to use this and solve the equation first and represent in cartesian coordinate?
$endgroup$
– ardentcoder
Apr 5 at 18:00












$begingroup$
@ardentcoder I'll edit my answer.
$endgroup$
– blub
Apr 5 at 18:01




$begingroup$
@ardentcoder I'll edit my answer.
$endgroup$
– blub
Apr 5 at 18:01












$begingroup$
Thank you . Will proceed with this.
$endgroup$
– ardentcoder
Apr 5 at 18:33




$begingroup$
Thank you . Will proceed with this.
$endgroup$
– ardentcoder
Apr 5 at 18:33










ardentcoder is a new contributor. Be nice, and check out our Code of Conduct.









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ardentcoder is a new contributor. Be nice, and check out our Code of Conduct.












ardentcoder is a new contributor. Be nice, and check out our Code of Conduct.











ardentcoder is a new contributor. Be nice, and check out our Code of Conduct.














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